Fizz Buzz 20 XP Medium

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Fizz Buzz is one of the most famous coding challenges in the world! It's used in job interviews to test if someone actually knows how to code. 🏆

💡 The Rules:

Loop through numbers 1 to 15
If a number is divisible by 3, print Fizz
If a number is divisible by 5, print Buzz
If divisible by BOTH 3 and 5, print FizzBuzz
Otherwise, just print the number

The modulo operator % gives the remainder of division. If the remainder is 0, the number is evenly divisible:

print(6 % 3)   # 0 → 6 IS divisible by 3
print(7 % 3)   # 1 → 7 is NOT divisible by 3
print(15 % 5)  # 0 → 15 IS divisible by 5
print(15 % 3)  # 0 → 15 IS also divisible by 3!

⚠️ Common Mistake: You MUST check "divisible by both 3 AND 5" first! Why? Because 15 is divisible by 3, so if you check that first, you'll print "Fizz" and never reach "FizzBuzz".

Step by step for first few numbers:

1 → not divisible by 3 or 5 → print 1
2 → not divisible by 3 or 5 → print 2
3 → divisible by 3 → print Fizz
4 → nothing → print 4
5 → divisible by 5 → print Buzz
15 → divisible by BOTH → print FizzBuzz

📋 Instructions

Implement the FizzBuzz challenge for numbers 1-15: Expected output: ``` 1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz ``` **Important**: Check divisibility by both 3 AND 5 first!

Use a for loop: for i in range(1, 16). Check i % 15 == 0 FIRST (FizzBuzz), then i % 3 == 0 (Fizz), then i % 5 == 0 (Buzz), else print(i).

⚠️ Try solving it yourself first — you'll learn more!

print(6 % 3)   # 0 → 6 IS divisible by 3
print(7 % 3)   # 1 → 7 is NOT divisible by 3
print(15 % 5)  # 0 → 15 IS divisible by 5
print(15 % 3)  # 0 → 15 IS also divisible by 3!

🧪 Test Cases

Input

Run your code

Expected

1
2
Fizz
...

Expected output (15 lines)

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main.py

Hi! I'm Rex 👋

Output

Ready. Press ▶ Run or Ctrl+Enter.

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